Integrand size = 29, antiderivative size = 152 \[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=-\frac {9 a x \sqrt {a-b x^2} \left (a+b x^2\right )}{8 \sqrt {a^2-b^2 x^4}}-\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}}+\frac {19 a^2 \sqrt {a-b x^2} \sqrt {a+b x^2} \text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{8 \sqrt {b} \sqrt {a^2-b^2 x^4}} \]
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Time = 0.04 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {1166, 427, 396, 223, 212} \[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\frac {19 a^2 \sqrt {a-b x^2} \sqrt {a+b x^2} \text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{8 \sqrt {b} \sqrt {a^2-b^2 x^4}}-\frac {9 a x \sqrt {a-b x^2} \left (a+b x^2\right )}{8 \sqrt {a^2-b^2 x^4}}-\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}} \]
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Rule 212
Rule 223
Rule 396
Rule 427
Rule 1166
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt {a-b x^2} \sqrt {a+b x^2}\right ) \int \frac {\left (a-b x^2\right )^2}{\sqrt {a+b x^2}} \, dx}{\sqrt {a^2-b^2 x^4}} \\ & = -\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}}+\frac {\left (\sqrt {a-b x^2} \sqrt {a+b x^2}\right ) \int \frac {5 a^2 b-9 a b^2 x^2}{\sqrt {a+b x^2}} \, dx}{4 b \sqrt {a^2-b^2 x^4}} \\ & = -\frac {9 a x \sqrt {a-b x^2} \left (a+b x^2\right )}{8 \sqrt {a^2-b^2 x^4}}-\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}}+\frac {\left (19 a^2 \sqrt {a-b x^2} \sqrt {a+b x^2}\right ) \int \frac {1}{\sqrt {a+b x^2}} \, dx}{8 \sqrt {a^2-b^2 x^4}} \\ & = -\frac {9 a x \sqrt {a-b x^2} \left (a+b x^2\right )}{8 \sqrt {a^2-b^2 x^4}}-\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}}+\frac {\left (19 a^2 \sqrt {a-b x^2} \sqrt {a+b x^2}\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {a+b x^2}}\right )}{8 \sqrt {a^2-b^2 x^4}} \\ & = -\frac {9 a x \sqrt {a-b x^2} \left (a+b x^2\right )}{8 \sqrt {a^2-b^2 x^4}}-\frac {x \left (a-b x^2\right )^{3/2} \left (a+b x^2\right )}{4 \sqrt {a^2-b^2 x^4}}+\frac {19 a^2 \sqrt {a-b x^2} \sqrt {a+b x^2} \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{8 \sqrt {b} \sqrt {a^2-b^2 x^4}} \\ \end{align*}
Time = 2.71 (sec) , antiderivative size = 123, normalized size of antiderivative = 0.81 \[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\frac {1}{8} \left (\frac {x \left (-11 a+2 b x^2\right ) \sqrt {a^2-b^2 x^4}}{\sqrt {a-b x^2}}-\frac {19 a^2 \log \left (-a+b x^2\right )}{\sqrt {b}}+\frac {19 a^2 \log \left (a b x-b^2 x^3+\sqrt {b} \sqrt {a-b x^2} \sqrt {a^2-b^2 x^4}\right )}{\sqrt {b}}\right ) \]
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Time = 0.23 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.62
method | result | size |
default | \(\frac {\sqrt {-b^{2} x^{4}+a^{2}}\, \left (2 b^{\frac {3}{2}} x^{3} \sqrt {b \,x^{2}+a}-11 a x \sqrt {b}\, \sqrt {b \,x^{2}+a}+19 \ln \left (\sqrt {b}\, x +\sqrt {b \,x^{2}+a}\right ) a^{2}\right )}{8 \sqrt {-b \,x^{2}+a}\, \sqrt {b \,x^{2}+a}\, \sqrt {b}}\) | \(94\) |
risch | \(\frac {x \left (-2 b \,x^{2}+11 a \right ) \sqrt {b \,x^{2}+a}\, \sqrt {\frac {\left (-b \,x^{2}+a \right ) \left (-b^{2} x^{4}+a^{2}\right )}{\left (b \,x^{2}-a \right )^{2}}}\, \left (b \,x^{2}-a \right )}{8 \sqrt {-b \,x^{2}+a}\, \sqrt {-b^{2} x^{4}+a^{2}}}-\frac {19 a^{2} \ln \left (\sqrt {b}\, x +\sqrt {b \,x^{2}+a}\right ) \sqrt {\frac {\left (-b \,x^{2}+a \right ) \left (-b^{2} x^{4}+a^{2}\right )}{\left (b \,x^{2}-a \right )^{2}}}\, \left (b \,x^{2}-a \right )}{8 \sqrt {b}\, \sqrt {-b \,x^{2}+a}\, \sqrt {-b^{2} x^{4}+a^{2}}}\) | \(182\) |
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none
Time = 0.26 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.74 \[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\left [\frac {19 \, {\left (a^{2} b x^{2} - a^{3}\right )} \sqrt {b} \log \left (\frac {2 \, b^{2} x^{4} - a b x^{2} - 2 \, \sqrt {-b^{2} x^{4} + a^{2}} \sqrt {-b x^{2} + a} \sqrt {b} x - a^{2}}{b x^{2} - a}\right ) - 2 \, \sqrt {-b^{2} x^{4} + a^{2}} {\left (2 \, b^{2} x^{3} - 11 \, a b x\right )} \sqrt {-b x^{2} + a}}{16 \, {\left (b^{2} x^{2} - a b\right )}}, \frac {19 \, {\left (a^{2} b x^{2} - a^{3}\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {-b^{2} x^{4} + a^{2}} \sqrt {-b x^{2} + a} \sqrt {-b}}{b^{2} x^{3} - a b x}\right ) - \sqrt {-b^{2} x^{4} + a^{2}} {\left (2 \, b^{2} x^{3} - 11 \, a b x\right )} \sqrt {-b x^{2} + a}}{8 \, {\left (b^{2} x^{2} - a b\right )}}\right ] \]
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\[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\int \frac {\left (a - b x^{2}\right )^{\frac {5}{2}}}{\sqrt {- \left (- a + b x^{2}\right ) \left (a + b x^{2}\right )}}\, dx \]
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\[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\int { \frac {{\left (-b x^{2} + a\right )}^{\frac {5}{2}}}{\sqrt {-b^{2} x^{4} + a^{2}}} \,d x } \]
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\[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\int { \frac {{\left (-b x^{2} + a\right )}^{\frac {5}{2}}}{\sqrt {-b^{2} x^{4} + a^{2}}} \,d x } \]
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Timed out. \[ \int \frac {\left (a-b x^2\right )^{5/2}}{\sqrt {a^2-b^2 x^4}} \, dx=\int \frac {{\left (a-b\,x^2\right )}^{5/2}}{\sqrt {a^2-b^2\,x^4}} \,d x \]
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